Difference between revisions of "Bayes' Theorem"
Enderramsby (talk | contribs) m |
Enderramsby (talk | contribs) |
||
| (One intermediate revision by the same user not shown) | |||
| Line 2: | Line 2: | ||
Let <math>E_1</math> and <math>E_2</math> be two events, and <math>P(E_1 | E_2)</math> the [[probability]] of <math>E_1</math> dependent on <math>E_2.</math> Then <cmath>P(E_1 | E_2) = \dfrac{P(E_2 | E_1) \cdot P(E_1)}{P(E_2)}.</cmath> | Let <math>E_1</math> and <math>E_2</math> be two events, and <math>P(E_1 | E_2)</math> the [[probability]] of <math>E_1</math> dependent on <math>E_2.</math> Then <cmath>P(E_1 | E_2) = \dfrac{P(E_2 | E_1) \cdot P(E_1)}{P(E_2)}.</cmath> | ||
| − | |||
~[[User:Enderramsby|enderramsby]] | ~[[User:Enderramsby|enderramsby]] | ||
| Line 8: | Line 7: | ||
{{stub}} | {{stub}} | ||
| + | |||
| + | [[Category:Probability]] | ||
Latest revision as of 11:32, 2 August 2022
Bayes' Theorem:
Let 
and 
be two events, and 
the probability of dependent on 
Then ![\[P(E_1 | E_2) = \dfrac{P(E_2 | E_1) \cdot P(E_1)}{P(E_2)}.\]](http://latex.artofproblemsolving.com/8/7/8/8788a644959ccf9f27057cf0f963e442c51bf3ff.png)
This article is a stub. Help us out by expanding it.
