Difference between revisions of "2021 Fall AMC 10A Problems/Problem 8"

Latest revision as of 02:35, 8 September 2024

Problem

A two-digit positive integer is said to be $\emph{cuddly}$ if it is equal to the sum of its nonzero tens digit and the square of its units digit. How many two-digit positive integers are cuddly?

$\textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }2\qquad\textbf{(D) }3\qquad\textbf{(E) }4$

Solution 1

Note that the number $\underline{xy} = 10x + y.$ By the problem statement, $10x + y = x + y^2 \implies 9x = y^2 - y \implies 9x = y(y-1).$ From this we see that $y(y-1)$ must be divisible by $9.$ This only happens when $y=9.$ Then, $x=8.$ Thus, there is only $\boxed{\textbf{(B) }1}$ cuddly number, which is $89.$

~NH14

Solution 2

If the tens digit is $a$ and the ones digit is $b$ then the number is $10a+b$ so we have the equation $10a + b = a + b^2$ . We can guess and check after narrowing the possible cuddly numbers down to $13,14,24,25,35,36,46,47,57,68,78,89,$ and $99$ . (We can narrow it down to these by just thinking about how $a$ 's value affects $b$ 's value and then check all the possiblities.) Checking all of these we get that there is only $\boxed{\textbf{(B) }1}$ 2-digit cuddly number, and it is $89$ . Yay!!!

~Andlind

Video Solution (HOW TO THINK CREATIVELY!!!)

https://youtu.be/u19JD85a9d0

~Education, the Study of Everything

Video Solution by TheBeautyofMath

https://youtu.be/ycRZHCOKTVk?t=391

~IceMatrix

Video Solution by WhyMath

https://youtu.be/knVmshj9SDs ~savannahsolver

Video Solution by HS Competition Academy

https://youtu.be/3Ji2_ZYIsPM

~Charles 3829

Video Solution

https://youtu.be/6XwPk7h8CU8

~Lucas

@@ Line 10: / Line 10: @@
 == Solution 2 ==
-If the tens digit is <math>a</math> and the ones digit is <math>b</math> then the number is <math>10+b</math> so we have the equation <math>10a + b = a + b^2</math>. We can guess and check after narrowing the possible cuddly numbers down to <math>13,14,24,25,35,36,46,47,57,68,78,89,</math> and <math>99</math>. (We can narrow it down to these by just thinking about how <math>a</math>'s value affects <math>b</math>'s value and then check all the possiblities.) Checking all of these we get that there is only <math>\boxed{1}</math> 2-digit cuddly number, and it is <math>89</math>.
+If the tens digit is <math>a</math> and the ones digit is <math>b</math> then the number is <math>10a+b</math> so we have the equation <math>10a + b = a + b^2</math>. We can guess and check after narrowing the possible cuddly numbers down to <math>13,14,24,25,35,36,46,47,57,68,78,89,</math> and <math>99</math>. (We can narrow it down to these by just thinking about how <math>a</math>'s value affects <math>b</math>'s value and then check all the possiblities.) Checking all of these we get that there is only <math>\boxed{\textbf{(B) }1}</math> 2-digit cuddly number, and it is <math>89</math>. Yay!!!
 ~Andlind
+==Video Solution (HOW TO THINK CREATIVELY!!!)==
+https://youtu.be/u19JD85a9d0
+~Education, the Study of Everything
+==Video Solution by TheBeautyofMath==
+https://youtu.be/ycRZHCOKTVk?t=391
+~IceMatrix
+==Video Solution by WhyMath==
+https://youtu.be/knVmshj9SDs ~savannahsolver
+==Video Solution by HS Competition Academy==
+https://youtu.be/3Ji2_ZYIsPM
+~Charles 3829
+==Video Solution==
+https://youtu.be/6XwPk7h8CU8
+~Lucas
 ==See Also==
 {{AMC10 box|year=2021 Fall|ab=A|num-b=7|num-a=9}}
 {{MAA Notice}}

2021 Fall AMC 10A (Problems • Answer Key • Resources)
Preceded by Problem 7	Followed by Problem 9
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