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| − | ==Problem==
| + | #REDIRECT [[2021_Fall_AMC_12B_Problems/Problem_1]] |
| − | What is the value of <math>1234+2341+3412+4123?</math>
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| − | <math>(\textbf{A})\: 10{,}000\qquad(\textbf{B}) \: 10{,}010\qquad(\textbf{C}) \: 10{,}110\qquad(\textbf{D}) \: 11{,}000\qquad(\textbf{E}) \: 11{,}110</math>
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| − | == Solution 1 ==
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| − | We see that <math>1, 2, 3,</math> and <math>4</math> each appear in the ones, tens, hundreds, and thousands digit exactly once. Since <math>1+2+3+4=10</math>, we find that the sum is equal to <cmath>10\cdot(1+10+100+1000)=\boxed{(\textbf{E})11,110}.</cmath>
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| − | Note: it is equally valid to manually add all 4 numbers together to get the answer.
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| − | ~kingofpineapplz
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| − | ==See Also==
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| − | {{AMC10 box|year=2021 Fall|ab=B|before=First Problem|num-a=2}}
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| − | {{MAA Notice}}
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