Difference between revisions of "2007 Cyprus MO/Lyceum/Problem 24"
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==Solution== | ==Solution== | ||
| − | If the TV original prices are <math>x,\ y</math>, then <math>\frac{11}{10}x = 198</math> and <math>\frac 9{10}y = 198</math>; <math>x = 180</math> and <math>y = 220</math> totaling <math>400</math>; he loses <math>2(198) - 400 = -4 \Longrightarrow \mathrm{E}</math>. | + | If the TV original prices are <math>x,\ y</math>, then <math>\frac{11}{10}x = 198</math> and <math>\frac 9{10}y = 198</math>; <math>x = 180</math> and <math>y = 220</math> totaling <math>400</math>; he loses <math>2(198) - 400 = -4 \Longrightarrow \boxed{\mathrm{E}}</math>. |
==See also== | ==See also== | ||
| − | {{CYMO box|year=2007|l=Lyceum|num-b= | + | {{CYMO box|year=2007|l=Lyceum|num-b=23|num-a=25}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
Latest revision as of 01:33, 19 January 2024
Problem
Costas sold two televisions for €198 each. From the sale of the first one he made a profit of 10% on its value and from the sale of the second one, he had a loss of 10% on its value. After the sale of the two televisions Costas had in total
Solution
If the TV original prices are 
, then 
and 
; 
and 
totaling 
; he loses 
.
See also
| 2007 Cyprus MO, Lyceum (Problems) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
