Difference between revisions of "1985 AJHSME Problem 16"
Coolmath34 (talk | contribs) (Created page with "== Problem == The ratio of boys to girls in Mr. Brown's math class is <math>2:3</math>. If there are <math>30</math> students in the class, how many more girls than boys are...") |
(→In-depth Solution by BoundlessBrain!) |
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<math>\text{(A)}\ 10 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 6 \qquad \text{(E)}\ 2</math> | <math>\text{(A)}\ 10 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 6 \qquad \text{(E)}\ 2</math> | ||
| − | == Solution == | + | ==In-depth Solution by BoundlessBrain!== |
| + | https://youtu.be/LWBB5i_kmwE | ||
| + | |||
| + | ==Solution== | ||
If there are <math>30</math> students in the class, there are <math>\frac{2}{2+3} \cdot 30 = 12</math> boys and <math>\frac{3}{2+3} \cdot 30 = 18</math> girls. So, there are <math>\boxed{\text{(D)} 6}</math> more girls than boys. | If there are <math>30</math> students in the class, there are <math>\frac{2}{2+3} \cdot 30 = 12</math> boys and <math>\frac{3}{2+3} \cdot 30 = 18</math> girls. So, there are <math>\boxed{\text{(D)} 6}</math> more girls than boys. | ||
Latest revision as of 15:03, 4 July 2023
Problem
The ratio of boys to girls in Mr. Brown's math class is 
. If there are 
students in the class, how many more girls than boys are in the class?
In-depth Solution by BoundlessBrain!
Solution
If there are students in the class, there are 
boys and 
girls. So, there are 
more girls than boys.
