Difference between revisions of "1998 CEMC Gauss (Grade 7) Problems/Problem 4"
Coolmath34 (talk | contribs) (Created page with "== Problem 4 == Jean writes five tests and achieves the marks shown on the graph. What is her average mark on these five tests? [insert bar graph with 5 bars: 80, 70, 60, 90,...") |
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| + | |||
| + | == Solution == | ||
| + | When 80 + 70 + 60 + 90 + 80 added together the total is 380. | ||
| + | Next 380 ÷ 5 = 76 | ||
| + | 80 | ||
| + | 70 | ||
| + | 60 | ||
| + | 90 | ||
| + | 80 | ||
| + | +___ | ||
| + | 380 ÷ 5 = 76 | ||
| + | |||
| + | Therefore when 80+70+60+90+80 are added together the total is 380 ÷ 5 = 76 so (B) 76 is correct answer. | ||
| + | |||
| + | -edited by De-math-wiz | ||
Latest revision as of 17:28, 12 May 2024
Problem 4
Jean writes five tests and achieves the marks shown on the graph. What is her average mark on these five tests?
[insert bar graph with 5 bars: 80, 70, 60, 90, 80]
Solution
The average of the 
tests is 
The answer is 
.
-edited by coolmath34
Solution
When 80 + 70 + 60 + 90 + 80 added together the total is 380. Next 380 ÷ 5 = 76
80 70 60 90 80
+___
380 ÷ 5 = 76
Therefore when 80+70+60+90+80 are added together the total is 380 ÷ 5 = 76 so (B) 76 is correct answer.
-edited by De-math-wiz
