Difference between revisions of "2013 AMC 10A Problems/Problem 1"
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There are five miles which need to be traveled. The cost of these five miles is <math>(0.25\cdot5) = 1.25</math>. Adding this to <math>1.50</math>, we get <math>\boxed{\textbf{(C) }2.75}</math> | There are five miles which need to be traveled. The cost of these five miles is <math>(0.25\cdot5) = 1.25</math>. Adding this to <math>1.50</math>, we get <math>\boxed{\textbf{(C) }2.75}</math> | ||
| + | ==Video Solution (CREATIVE THINKING)== | ||
| + | https://youtu.be/4XDyloZUY48 | ||
| + | ~Education, the Study of Everything | ||
| + | |||
| + | |||
| + | ==Video Solution== | ||
| + | https://youtu.be/hIklCIgfxcg | ||
| + | |||
| + | ~savannahsolver | ||
==See Also== | ==See Also== | ||
Latest revision as of 12:11, 1 July 2023
Problem
A taxi ride costs 
plus 
per mile traveled. How much does a 
-mile taxi ride cost?
Solution
There are five miles which need to be traveled. The cost of these five miles is 
. Adding this to 
, we get 
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
| 2013 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
