Difference between revisions of "1976 AHSME Problems/Problem 7"
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If <math>-1 < x < 1</math>, then the first factor is positive, and the second factor is also positive. | If <math>-1 < x < 1</math>, then the first factor is positive, and the second factor is also positive. | ||
− | If <math>x > 1</math>, the first factor is | + | If <math>x > 1</math>, the first factor is negative, but the second factor is positive. |
Combining this with the rules for signs and multiplication, we find that the expression is positive when <math>x < -1</math> or when <math>-1 < x < 1</math>, so our answer is <math>\boxed{\textbf{(C)}}</math> and we are done. | Combining this with the rules for signs and multiplication, we find that the expression is positive when <math>x < -1</math> or when <math>-1 < x < 1</math>, so our answer is <math>\boxed{\textbf{(C)}}</math> and we are done. |
Latest revision as of 21:02, 24 September 2020
If is a real number, then the quantity is positive if and only if
Solution
We divide our solution into three cases: that of , that of , and that of . (When or , the expression is zero, therefore not positive.)
If , then the first factor is negative, and the second factor is also negative.
If , then the first factor is positive, and the second factor is also positive.
If , the first factor is negative, but the second factor is positive.
Combining this with the rules for signs and multiplication, we find that the expression is positive when or when , so our answer is and we are done.
See also
1976 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.