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| − | ==Instructions==
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| − | 1. All rules of a regular AMC 10 apply.
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| − | 2. Please submit your answers in a DM to me (Lcz).
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| − | 3. Don't cheat.
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| − | Here's the problems!
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| − | ==Problem 1==
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| − | Find the value of <math>2^{0+1+2}+2+0(1+(2))+20(12)</math>.
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| − | <math>\textbf{(A)}\ 8 \qquad\textbf{(B)}\ 248 \qquad\textbf{(C)}\ 250 \qquad\textbf{(D)}\ 252 \qquad\textbf{(E)}\ 254</math>
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| − | ==Problem 2==
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| − | If <math>|x-2|=0</math>, and <math>|y-3|=1</math>, find the sum of all possible values of <math>|xy|</math>.
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| − | <math>\textbf{(A)}\ 0 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 8 \qquad\textbf{(D)}\ 12 \qquad\textbf{(E)}\ 16</math>
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| − | ==Problem 3==
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| − | Jack and Jill play a (bad) game on a number line which contains the integers. Jack starts at <math>-2</math>, and Jill starts at <math>18</math>. Every turn, the judge flip a standard six sided die. If the number rolled is a square number, Jack moves to the right <math>10</math> units. Otherwise, Jill moves to the left <math>5</math> units. What is the probability that it takes exactly <math>3</math> moves for Jack and Jill to be on the same unit?
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| − | oops gotta go eat lol
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| − | <math>\textbf{(A)}\ \qquad\textbf{(B)}\ 248 \qquad\textbf{(C)}\ 250 \qquad\textbf{(D)}\ 252 \qquad\textbf{(E)}\ 254</math>
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