Difference between revisions of "1955 AHSME Problems/Problem 4"
Awesomechoco (talk | contribs) (Created page with "==Problem== The equality <math>\frac{1}{x-1}=\frac{2}{x-2}</math> is satisfied by: <math>\textbf{(A)}\ \text{no real values of }x\qquad\textbf{(B)}\ \text{either }x=1\text{...") |
Awesomechoco (talk | contribs) (→Problem) |
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<math>\textbf{(A)}\ \text{no real values of }x\qquad\textbf{(B)}\ \text{either }x=1\text{ or }x=2\qquad\textbf{(C)}\ \text{only }x=1\\ \textbf{(D)}\ \text{only }x=2\qquad\textbf{(E)}\ \text{only }x=0</math> | <math>\textbf{(A)}\ \text{no real values of }x\qquad\textbf{(B)}\ \text{either }x=1\text{ or }x=2\qquad\textbf{(C)}\ \text{only }x=1\\ \textbf{(D)}\ \text{only }x=2\qquad\textbf{(E)}\ \text{only }x=0</math> | ||
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| + | ==Solution== | ||
| + | |||
| + | From this equality, we get (x&-1)*2 | ||
Revision as of 22:47, 6 July 2018
Problem
The equality 
is satisfied by:
Solution
From this equality, we get (x&-1)*2
