Difference between revisions of "2006 AMC 10A Problems/Problem 3"
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== See Also == | == See Also == | ||
*[[2006 AMC 10A Problems]] | *[[2006 AMC 10A Problems]] | ||
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| + | *[[2006 AMC 10A Problems/Problem 2|Previous Problem]] | ||
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| + | *[[2006 AMC 10A Problems/Problem 4|Next Problem]] | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 14:37, 4 August 2006
Problem
The ratio of Mary's age to Alice's age is 3:5. Alice is 30 years old. How many years old is Mary?
Solution
We can create the equation
Where x is Mary's age. Simplfying yields
