Difference between revisions of "2018 AMC 10B Problems/Problem 1"
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By dividing the each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid which makes <math>90</math> pieces. Thus, the answer is <math>\boxed{A}</math>. | By dividing the each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid which makes <math>90</math> pieces. Thus, the answer is <math>\boxed{A}</math>. | ||
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| + | ==See Also== | ||
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| + | {{AMC10 box|year=2018|ab=B|before=First Problem|num-a=2}} | ||
| + | {{AMC12 box|year=2018|ab=B|before=First Problem|num-a=2}} | ||
| + | {{MAA Notice}} | ||
Revision as of 13:59, 16 February 2018
Kate bakes 20-inch by 18-inch pan of cornbread. The cornbread is cut into pieces that measure 2 inches by 2 inches. How many pieces of cornbread does the pan contain?
Solution 1
The area of the pan is 
= 
. Since the area of each piece is 
, there are 360/40 = 90 pieces. Thus, the answer is 
.
Solution 2
By dividing the each of the dimensions by 
, we get a 
grid which makes 
pieces. Thus, the answer is .
See Also
| 2018 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2018 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
