Difference between revisions of "2006 AMC 10B Problems/Problem 4"
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== See Also == | == See Also == | ||
*[[2006 AMC 10B Problems]] | *[[2006 AMC 10B Problems]] | ||
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+ | *[[2006 AMC 10B Problems/Problem 5|Next Problem]] |
Revision as of 13:52, 2 August 2006
Problem
Circles of diameter 1 inch and 3 inches have the same center. The smaller circle is painted red, and the portion outside the smaller circle and inside the larger circle is painted blue. What is the ratio of the blue-painted area to the red-painted area?
Solution
The area painted red is equal to the area of the smaller circle and the area painted blue is equal to the area of the larger circle minus the area of the smaller circle.
So:
So the desired ratio is: