Difference between revisions of "2009 AMC 8 Problems/Problem 24"
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==Solution== | ==Solution== | ||
| − | Because <math> B+A=A </math>, <math>B</math> must be <math>0</math> | + | Because <math> B+A=A </math>, <math>B</math> must be <math>0</math>. |
Next, because <math> B-A=A\implies0-A=A,</math> we get <math>A=5</math> | Next, because <math> B-A=A\implies0-A=A,</math> we get <math>A=5</math> | ||
Revision as of 14:58, 26 August 2017
Problem
The letters 
, 
, 
and 
represent digits. If 
and 
,what digit does represent?
Solution
Because 
, must be 
.
Next, because 
we get 
Now we can rewrite this as 
. Therefore, 
Finally, 
, So we have 
See Also
| 2009 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
