Difference between revisions of "Heron's Formula"

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'''Heron's formula''' (sometimes called Hero's formula) is a method for finding the [[area]] of a [[triangle]] given only the three side lengths.
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'''Heron's formula''' (sometimes called Hero's formula) is a [[mathematical formula | formula]] for finding the [[area]] of a [[triangle]] given only the three side lengths.
  
 
=== Definition ===
 
=== Definition ===
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where the [[semi-perimeter]] <math>s=\frac{a+b+c}{2}</math>.
 
where the [[semi-perimeter]] <math>s=\frac{a+b+c}{2}</math>.
  
=== Proof ===
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 +
== Proof ==
  
 
<math>[ABC]=\frac{ab}{2}\sin C</math>
 
<math>[ABC]=\frac{ab}{2}\sin C</math>
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<math>=\sqrt{s(s-a)(s-b)(s-c)}</math>
 
<math>=\sqrt{s(s-a)(s-b)(s-c)}</math>
  
=== See Also ===
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 +
== See Also ==
  
 
* [[Brahmagupta's formula]]
 
* [[Brahmagupta's formula]]

Revision as of 17:31, 25 July 2006

Heron's formula (sometimes called Hero's formula) is a formula for finding the area of a triangle given only the three side lengths.

Definition

For any triangle with side lengths ${a}, {b}, {c}$, the area ${A}$ can be found using the following formula:

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where the semi-perimeter $s=\frac{a+b+c}{2}$.


Proof

$[ABC]=\frac{ab}{2}\sin C$

$=\frac{ab}{2}\sqrt{1-\cos^2 C}$

$=\frac{ab}{2}\sqrt{1-(\frac{a^2+b^2-c^2}{2ab})^2}$

$=\sqrt{\frac{a^2b^2}{4}(1-\frac{(a^2+b^2-c^2)^2}{4a^2b^2})}$

$=\sqrt{\frac{4a^2b^2-(a^2+b^2-c^2)^2}{16}}$

$=\sqrt{\frac{(2ab+a^2+b^2-c^2)(2ab-a^2-b^2+c^2)}{16}}$

$=\sqrt{\frac{((a+b)^2-c^2)(c^2-(a-b)^2)}{16}}$

$=\sqrt{\frac{(a+b+c)(a+b-c)(b+c-a)(a+c-b)}{16}}$

$=\sqrt{s(s-a)(s-b)(s-c)}$


See Also