Difference between revisions of "1975 AHSME Problems/Problem 7"
(Created page with "For which non-zero real numbers <math>x</math> is <math>\frac{|x-|x|\-|}{x}</math> a positive integers? <math>\textbf{(A)}\ \text{for negative } x \text{ only} \qquad \\ \te...") |
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| − | Notice that if <math>x</math> is negative, then the whole thing would amount to a negative number. Also notice that if <math>x</math> is positive, then <math>|x-|x|\-|</math> would be <math>0</math>, hence the whole thing would amount to <math>0</math>. Therefore, <math>\frac{|x-|x|\-|}{x}</math> is positive <math>\boxed{\textbf{(E) } \text{for no non-zero real numbers} x}</math>. | + | Notice that if <math>x</math> is negative, then the whole thing would amount to a negative number. Also notice that if <math>x</math> is positive, then <math>|x-|x|\-|</math> would be <math>0</math>, hence the whole thing would amount to <math>0</math>. Therefore, <math>\frac{|x-|x|\-|}{x}</math> is positive <math>\boxed{\textbf{(E) } \text{for no non-zero real numbers}\ \x}</math>. |
Revision as of 12:26, 15 December 2016
For which non-zero real numbers 
is 
a positive integers?
Solution
Solution by e_power_pi_times_i
Notice that if is negative, then the whole thing would amount to a negative number. Also notice that if is positive, then 
would be 
, hence the whole thing would amount to . Therefore, is positive $\boxed{\textbf{(E) } \text{for no non-zero real numbers}\ \x}$ (Error compiling LaTeX. Unknown error_msg).
