Difference between revisions of "1958 AHSME Problems/Problem 27"
(Created page with "== Problem == The points <math> (2,\minus{}3)</math>, <math> (4,3)</math>, and <math> (5, k/2)</math> are on the same straight line. The value(s) of <math> k</math> is (are): <m...") |
(→Solution) |
||
| (4 intermediate revisions by 2 users not shown) | |||
| Line 1: | Line 1: | ||
== Problem == | == Problem == | ||
| − | The points <math> (2, | + | The points <math> (2,-3)</math>, <math> (4,3)</math>, and <math> (5, k/2)</math> are on the same straight line. The value(s) of <math> k</math> is (are): |
<math> \textbf{(A)}\ 12\qquad | <math> \textbf{(A)}\ 12\qquad | ||
| − | \textbf{(B)}\ | + | \textbf{(B)}\ -12\qquad |
\textbf{(C)}\ \pm 12\qquad | \textbf{(C)}\ \pm 12\qquad | ||
\textbf{(D)}\ {12}\text{ or }{6}\qquad | \textbf{(D)}\ {12}\text{ or }{6}\qquad | ||
\textbf{(E)}\ {6}\text{ or }{6\frac{2}{3}}</math> | \textbf{(E)}\ {6}\text{ or }{6\frac{2}{3}}</math> | ||
| − | |||
== Solution == | == Solution == | ||
| − | <math>\ | + | First find the slope. Then use the point-slope formula to find the equation of the line. Then substitute 5 for x to find y. |
| + | <math>\text{(A)}12</math> | ||
== See Also == | == See Also == | ||
Latest revision as of 09:19, 3 December 2016
Problem
The points 
, 
, and 
are on the same straight line. The value(s) of 
is (are):
Solution
First find the slope. Then use the point-slope formula to find the equation of the line. Then substitute 5 for x to find y.
See Also
| 1958 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 26 |
Followed by Problem 28 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
