Difference between revisions of "1994 AJHSME Problems/Problem 3"
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==Problem== | ==Problem== | ||
− | Each day Maria must work <math>8</math> hours | + | Each day Maria must work <math>8</math> hours. This does not include the <math>45</math> minutes she takes for lunch. If she begins working at <math>\text{7:25 A.M.}</math> and takes her lunch break at noon, then her working day will end at |
<math>\text{(A)}\ \text{3:40 P.M.} \qquad \text{(B)}\ \text{3:55 P.M.} \qquad \text{(C)}\ \text{4:10 P.M.} \qquad \text{(D)}\ \text{4:25 P.M.} \qquad \text{(E)}\ \text{4:40 P.M.}</math> | <math>\text{(A)}\ \text{3:40 P.M.} \qquad \text{(B)}\ \text{3:55 P.M.} \qquad \text{(C)}\ \text{4:10 P.M.} \qquad \text{(D)}\ \text{4:25 P.M.} \qquad \text{(E)}\ \text{4:40 P.M.}</math> | ||
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8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math> | 8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at <math>\boxed{\text{(C)}\ \text{4:10 P.M.}}</math> | ||
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==See Also== | ==See Also== | ||
{{AJHSME box|year=1994|num-b=2|num-a=4}} | {{AJHSME box|year=1994|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 12:17, 30 October 2016
Problem
Each day Maria must work hours. This does not include the minutes she takes for lunch. If she begins working at and takes her lunch break at noon, then her working day will end at
Solution
8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at
See Also
1994 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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