Difference between revisions of "1992 AHSME Problems/Problem 5"
(Created page with "== Problem == <math>6^6+6^6+6^6+6^6+6^6+6^6=</math> <math>\text{(A) 6^6} \quad \text{(B) } 6^7\quad \text{(C) } 36^6\quad \text{(D) } 6^{36}\quad \text{(E) } 36^{36}</math> ==...") |
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<math>6^6+6^6+6^6+6^6+6^6+6^6=</math> | <math>6^6+6^6+6^6+6^6+6^6+6^6=</math> | ||
| − | <math>\text{(A) 6^6 | + | <math>\text{(A) } 6^6 \quad |
\text{(B) } 6^7\quad | \text{(B) } 6^7\quad | ||
\text{(C) } 36^6\quad | \text{(C) } 36^6\quad | ||
| Line 10: | Line 10: | ||
== Solution == | == Solution == | ||
| − | <math>\ | + | We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}</math>. |
== See also == | == See also == | ||
Latest revision as of 15:21, 5 August 2016
Problem
Solution
We notice that 
.
See also
| 1992 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
