Difference between revisions of "1983 AHSME Problems/Problem 5"
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==Solution== | ==Solution== | ||
<asy> | <asy> | ||
| − | A=(0, | + | pair A,B,C; |
| − | B=( | + | A = (0,0); |
| − | C=(0, | + | B = (3,0); |
| − | + | C = (0,1); | |
| − | + | draw(A--B--C--A); | |
| + | draw(rightanglemark(B,A,C,8)); | ||
| + | label("$A$",A,SW); | ||
| + | label("$B$",B,SE); | ||
| + | label("$C$",C,N); | ||
| + | label("$3$",B/2,S); | ||
| + | label("$1$",C/2,W); | ||
| + | label("$\sqrt{10}$",(C+B)/2,NE); | ||
</asy> | </asy> | ||
Revision as of 19:28, 18 May 2016
Problem 5
Triangle 
has a right angle at 
. If 
, then 
is
Solution
![[asy] pair A,B,C; A = (0,0); B = (3,0); C = (0,1); draw(A--B--C--A); draw(rightanglemark(B,A,C,8)); label("$A$",A,SW); label("$B$",B,SE); label("$C$",C,N); label("$3$",B/2,S); label("$1$",C/2,W); label("$\sqrt{10}$",(C+B)/2,NE); [/asy]](http://latex.artofproblemsolving.com/f/7/9/f79fa3de0726b6a6cc5f8ebee031fa281fe7fd25.png)
See Also
| 1983 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
