Difference between revisions of "1990 AHSME Problems/Problem 10"
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<asy>import three; | <asy>import three; | ||
unitsize(1cm);size(100); | unitsize(1cm);size(100); | ||
− | draw((0,0,0)--(0,1,0), | + | draw((0,0,0)--(0,1,0),red); |
draw((0,0,1)--(0,0,0)--(1,0,0)--(1,0,1),red); | draw((0,0,1)--(0,0,0)--(1,0,0)--(1,0,1),red); | ||
− | draw((0,0,1)--(1,0,1), | + | draw((0,0,1)--(1,0,1),red); |
draw((0,0,1)--(0,1,1)--(0,1,0)--(1,1,0)--(1,0,0),red); | draw((0,0,1)--(0,1,1)--(0,1,0)--(1,1,0)--(1,0,0),red); | ||
− | draw((1,1,0)--(1,1,1), | + | draw((1,1,0)--(1,1,1),red); |
draw((0,1,1)--(1,1,1)--(1,0,1),red); | draw((0,1,1)--(1,1,1)--(1,0,1),red); | ||
</asy> | </asy> |
Revision as of 02:50, 14 February 2016
Problem
An wooden cube is formed by gluing together unit cubes. What is the greatest number of unit cubes that can be seen from a single point?
Solution
The best angle for cube viewing is centered on the corner. Meaning three of the six faces are visible. So therefore, the answer is just counting the number of cubes on the three faces. Which is 330 or
See also
1990 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.