Difference between revisions of "1979 USAMO Problems"

(Problem 5)
(Problem 5)
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==Problem 5==
 
==Problem 5==
Let <math>A_1,A_2,...,A_{n+1}</math> be distinct subsets of <math>[n]</math> with <math>|A_1|=|A_2|=\cdots =|A_n|=3</math>.  Prove that <math>|A_i\cap A_j|=1</math> for some pair <math>\{i,j\}</math>. Note that <math>[n] = \{1, 2, 3, ..., n\}</math>, or, alternatively, <math>\{x: 1 \le x \le n\}</math>.
+
Let <math>A_1,A_2,...,A_{n+1}</math> be distinct subsets of <math>[n]</math> with <math>|A_1|=|A_2|=\cdots =|A_{n+1}|=3</math>.  Prove that <math>|A_i\cap A_j|=1</math> for some pair <math>\{i,j\}</math>. Note that <math>[n] = \{1, 2, 3, ..., n\}</math>, or, alternatively, <math>\{x: 1 \le x \le n\}</math>.
  
 
[[1979 USAMO Problems/Problem 5 | Solution]]
 
[[1979 USAMO Problems/Problem 5 | Solution]]

Revision as of 12:00, 24 December 2015

Problems from the 1979 USAMO.

Problem 1

Determine all non-negative integral solutions $(n_1,n_2,\dots , n_{14})$ if any, apart from permutations, of the Diophantine Equation $n_1^4+n_2^4+\cdots +n_{14}^4=1599$.

Solution

Problem 2

$N$ is the north pole. $A$ and $B$ are points on a great circle through $N$ equidistant from $N$. $C$ is a point on the equator. Show that the great circle through $C$ and $N$ bisects the angle $ACB$ in the spherical triangle $ABC$ (a spherical triangle has great circle arcs as sides).

Solution

Problem 3

$a_1, a_2, \ldots, a_n$ is an arbitrary sequence of positive integers. A member of the sequence is picked at random. Its value is $a$. Another member is picked at random, independently of the first. Its value is $b$. Then a third value, $c$. Show that the probability that $a + b + c$ is divisible by $3$ is at least $\frac14$.

Solution

Problem 4

$P$ lies between the rays $OA$ and $OB$. Find $Q$ on $OA$ and $R$ on $OB$ collinear with $P$ so that $\frac{1}{PQ}\plus{} \frac{1}{PR}$ (Error compiling LaTeX. Unknown error_msg) is as large as possible.

Solution

Problem 5

Let $A_1,A_2,...,A_{n+1}$ be distinct subsets of $[n]$ with $|A_1|=|A_2|=\cdots =|A_{n+1}|=3$. Prove that $|A_i\cap A_j|=1$ for some pair $\{i,j\}$. Note that $[n] = \{1, 2, 3, ..., n\}$, or, alternatively, $\{x: 1 \le x \le n\}$.

Solution

See Also

1979 USAMO (ProblemsResources)
Preceded by
1978 USAMO
Followed by
1980 USAMO
1 2 3 4 5
All USAMO Problems and Solutions

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