Difference between revisions of "1953 AHSME Problems/Problem 1"
| Line 3: | Line 3: | ||
</math>\textbf{(A)}\ 67 \text{ oranges} \qquad \textbf{(B)}\ 150 \text{ oranges} \qquad \textbf{(C)}\ 200\text{ oranges}\\ \textbf{(D)}\ \text{an infinite number of oranges}\qquad \textbf{(E)}\ \text{none of these}<math> | </math>\textbf{(A)}\ 67 \text{ oranges} \qquad \textbf{(B)}\ 150 \text{ oranges} \qquad \textbf{(C)}\ 200\text{ oranges}\\ \textbf{(D)}\ \text{an infinite number of oranges}\qquad \textbf{(E)}\ \text{none of these}<math> | ||
| − | + | Solution: | |
The boy buys </math>3<math> oranges for </math>10<math> cents or </math>1<math> orange for </math>\frac{10}{3}<math> cents. He sells them at </math>\frac{20}{5}=4<math> cents each. | The boy buys </math>3<math> oranges for </math>10<math> cents or </math>1<math> orange for </math>\frac{10}{3}<math> cents. He sells them at </math>\frac{20}{5}=4<math> cents each. | ||
Revision as of 13:11, 31 July 2015
A boy buys oranges at 
for 
cents. He will sell them at 
for 
cents. In order to make a profit of $$ (Error compiling LaTeX. Unknown error_msg)1.00
\textbf{(A)}\ 67 \text{ oranges} \qquad \textbf{(B)}\ 150 \text{ oranges} \qquad \textbf{(C)}\ 200\text{ oranges}\\ \textbf{(D)}\ \text{an infinite number of oranges}\qquad \textbf{(E)}\ \text{none of these}$Solution:
The boy buys$ (Error compiling LaTeX. Unknown error_msg)3
10
1
\frac{10}{3}
\frac{20}{5}=4
4-\frac{10}{3}=\frac{2}{3}$cents.
To make a profit of$ (Error compiling LaTeX. Unknown error_msg)100
\frac{100}{\frac{2}{3}}=\boxed{150}=\boxed{\text{B}}$
~mathsolver101
