Difference between revisions of "2015 AMC 10A Problems/Problem 23"
(Added problem) |
(fixed ans choices) |
||
| Line 1: | Line 1: | ||
| − | |||
==Problem== | ==Problem== | ||
The zeroes of the function <math>f(x)=x^2-ax+2a</math> are integers .What is the sum of the possible values of a? | The zeroes of the function <math>f(x)=x^2-ax+2a</math> are integers .What is the sum of the possible values of a? | ||
| − | <math> \textbf{(A)}\ | + | <math> \textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 16\qquad\textbf{(D)}}\ 17\qquad\textbf{(E)}\ 18</math> |
| + | |||
==Solution== | ==Solution== | ||
| + | |||
| + | SFFT. | ||
==See Also== | ==See Also== | ||
| − | {{AMC10 box|year=2015|ab=A|before= | + | {{AMC10 box|year=2015|ab=A|before=First Problem|num-a=2}} |
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 18:26, 4 February 2015
Problem
The zeroes of the function 
are integers .What is the sum of the possible values of a?
$\textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 16\qquad\textbf{(D)}}\ 17\qquad\textbf{(E)}\ 18$ (Error compiling LaTeX. Unknown error_msg)
Solution
SFFT.
See Also
| 2015 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
