Difference between revisions of "1968 AHSME Problems/Problem 19"

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[[Category: Introductory Algebra Problems]]
 
[[Category: Introductory Algebra Problems]]
 
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Revision as of 21:36, 9 January 2015

Problem

Let $n$ be the number of ways $10$ dollars can be changed into dimes and quarters, with at least one of each coin being used. Then $n$ equals:

$\text{(A) } 40\quad \text{(B) } 38\quad \text{(C) } 21\quad \text{(D) } 20\quad \text{(E) } 19$

Solution

$\fbox{E}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
[[1968 AHSME Problems/Problem {{{num-b}}}|Problem {{{num-b}}}]]
Followed by
[[1968 AHSME Problems/Problem {{{num-a}}}|Problem {{{num-a}}}]]
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