Difference between revisions of "User talk:Benq"

Line 1: Line 1:
<math>f(x)=\frac{f(\frac{1}{x})}{2}+2</math> <math>f(7)</math>
+
<math>f(x)=\frac{f(\frac{1}{x})}{2}+2</math> <math>f(7)</math> <math>f(x)</math>

Revision as of 16:48, 8 December 2014

$f(x)=\frac{f(\frac{1}{x})}{2}+2$ $f(7)$ $f(x)$