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Difference between revisions of "2014 AMC 8 Problems"

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[[2014 AMC 8 Problems/Problem 1|Solution]]
 
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==Problem 2==
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Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. What is the difference between the largest and the smallest number of coins he can use to pay her?
 
Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. What is the difference between the largest and the smallest number of coins he can use to pay her?
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\textbf{(A) }1\qquad\textbf{(B) }2\qquad\textbf{(C) }3\qquad\textbf{(D) }4\qquad \textbf{(E) }5
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<math>\textbf{(A) }1\qquad\textbf{(B) }2\qquad\textbf{(C) }3\qquad\textbf{(D) }4\qquad \textbf{(E) }5</math>
  
 
[[2014 AMC 8 Problems/Problem 2|Solution]]
 
[[2014 AMC 8 Problems/Problem 2|Solution]]
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==Problem 25=
 
==Problem 25=
  
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size(10cm); pathpen=black; pointpen=black;
 
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D(arc((-2,0),1,300,360));
 
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D(arc((0,0),1,0,180));
 
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D(arc((2,0),1,180,360));
 
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D(arc((4,0),1,0,180));
 
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D(arc((6,0),1,180,240));
 
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D((-1.5,1)--(5.5,1));
 
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D((-1.5,-1)--(5.5,-1));[/asy]</math>
 
  
  
 
[[2014 AMC 8 Problems/Problem 25|Solution]]
 
[[2014 AMC 8 Problems/Problem 25|Solution]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 21:40, 26 November 2014

Problem 1

Harry and Terry are each told to calculate $8-(2+5)$. Harry gets the correct answer. Terry ignores the parentheses and calculates $8-2+5$. If Harry's answer is $H$ and Terry's answer is $T$, what is $H-T$?

$\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad\textbf{(E) }10$

Solution

Problem 2

Paul owes Paula 35 cents and has a pocket full of 5-cent coins, 10-cent coins, and 25-cent coins that he can use to pay her. What is the difference between the largest and the smallest number of coins he can use to pay her? $\textbf{(A) }1\qquad\textbf{(B) }2\qquad\textbf{(C) }3\qquad\textbf{(D) }4\qquad \textbf{(E) }5$

Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution

Problem 7

Solution

Problem 8

Solution

Problem 9

Solution

Problem 10

Solution

Problem 11

Solution

Problem 12

Solution

Problem 13

Solution

Problem 14

Solution

Problem 15

Solution

Problem 16

Solution

Problem 17

Solution

Problem 18

Solution

Problem 19

Solution

Problem 20

Solution

Problem 21

Solution

Problem 22

Solution

Problem 23

Solution

Problem 24

Solution

=Problem 25

Solution The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

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