Difference between revisions of "1991 AJHSME Problems/Problem 3"
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Two hundred thousand times two hundred thousand equals | Two hundred thousand times two hundred thousand equals | ||
| − | <math>\text{(A)}\ \text{four hundred thousand} \qquad \text{(B)}\ \text{four million} \qquad \text{(C)}\ \text{forty thousand} \qquad \text{(D)}\ \text{four hundred million} \qquad \text{(E)}\ \text{forty billion}</math> | + | <math>\text{(A)}\ \text{four hundred thousand} \qquad |
| + | \text{(B)}\ \text{four million} \qquad | ||
| + | \text{(C)}\ \text{forty thousand} \qquad \\ | ||
| + | \text{(D)}\ \text{four hundred million} \qquad | ||
| + | \text{(E)}\ \text{forty billion}</math> | ||
==Solution== | ==Solution== | ||
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{{AJHSME box|year=1991|num-b=2|num-a=4}} | {{AJHSME box|year=1991|num-b=2|num-a=4}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 22:52, 8 October 2014
Problem
Two hundred thousand times two hundred thousand equals
Solution
Writing the numbers in scientific notation, we have
See Also
| 1991 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
