Difference between revisions of "1968 AHSME Problems/Problem 14"

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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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<math>\fbox{E}</math>
  
 
== See also ==
 
== See also ==

Revision as of 02:30, 29 September 2014

Problem

If $x$ and $y$ are non-zero numbers such that $x=1+\frac{1}{y}$ and $y=1+\frac{1}{x}$, then $y$ equals

$\text{(A) } x-1\quad \text{(B) } 1-x\quad \text{(C) } 1+x\quad \text{(D) } -x\quad \text{(E) } x$

Solution

$\fbox{E}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
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