Difference between revisions of "1991 AHSME Problems/Problem 14"
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(A) <math>200</math> (B) <math>201</math> (C) <math>202</math> (D) <math>203</math> (E) <math>204</math> | (A) <math>200</math> (B) <math>201</math> (C) <math>202</math> (D) <math>203</math> (E) <math>204</math> | ||
== Solution == | == Solution == | ||
| − | <math>\fbox{}</math> | + | <math>\fbox{C}</math> |
== See also == | == See also == | ||
Revision as of 14:54, 28 September 2014
Problem
If 
is the cube of a positive integer and 
is the number of positive integers that are divisors of , then could be
(A) 
(B) 
(C) 
(D) 
(E) 
Solution
See also
| 1991 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
