Difference between revisions of "2013 USAJMO Problems/Problem 6"
(Created page with "==Solution== Without loss of generality, let x < y < z. Then <math>\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}</math>.") |
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| − | Without loss of generality, let x | + | Without loss of generality, let <math>x \ge y \ge z</math>. Then <math>\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}</math>. |
Revision as of 09:55, 14 April 2014
Solution
Without loss of generality, let 
. Then 
.
