Difference between revisions of "Power of a Point Theorem/Introductory Problem 2"
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== Solution == | == Solution == | ||
| − | Applying the Power of a Point Theorem gives <math> 6\cdot x = 4\cdot 1 </math> or <math> x = \frac 23 </math> | + | Applying the Power of a Point Theorem gives <math> 6\cdot x = 4\cdot 1 </math>, or <math> x = \frac 23 </math> |
''Back to the [[Power of a Point Theorem]].'' | ''Back to the [[Power of a Point Theorem]].'' | ||
Revision as of 13:39, 3 July 2006
Problem
Find the value of 
in the following diagram.
Solution
Applying the Power of a Point Theorem gives 
, or 
Back to the Power of a Point Theorem.
