Difference between revisions of "Power of a Point Theorem/Introductory Problem 1"
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== Solution == | == Solution == | ||
| − | Applying the Power of a Point Theorem gives us <math> 3\cdot(3+5) = x (x+10) </math>. Expanding and simplifying we get <math> x^2 + 10x - 24 = 0 </math>. This factors as <math> (x+12)(x-2) = 0 </math> We discard the negative solution since distance must be positive. Thus <math> x=2 </math>. | + | Applying the Power of a Point Theorem gives us <math> 3\cdot(3+5) = x (x+10) </math>. Expanding and simplifying we get <math> x^2 + 10x - 24 = 0 </math>. This factors as <math> (x+12)(x-2) = 0 </math>. We discard the negative solution since distance must be positive. Thus <math> x=2 </math>. |
''Back to the [[Power of a Point Theorem]].'' | ''Back to the [[Power of a Point Theorem]].'' | ||
Revision as of 13:38, 3 July 2006
Problem
Find the value of 
in the following diagram:
Solution
Applying the Power of a Point Theorem gives us 
. Expanding and simplifying we get 
. This factors as 
. We discard the negative solution since distance must be positive. Thus 
.
Back to the Power of a Point Theorem.
