Difference between revisions of "1997 AHSME Problems/Problem 7"
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Thus, the answer is <math>6</math>, which is option <math>\boxed{D}</math>. | Thus, the answer is <math>6</math>, which is option <math>\boxed{D}</math>. | ||
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| + | == See also == | ||
| + | {{AHSME box|year=1997|num-b=6|num-a=8}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 13:12, 5 July 2013
Problem
The sum of seven integers is 
. What is the maximum number of the seven integers that can be larger than 
?
Solution
If the first six integers are 
, the last number can be 
. The sum of all seven integers will be .
However, if all seven integers are over , the smallest possible sum is 
.
Thus, the answer is 
, which is option 
.
See also
| 1997 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
