Difference between revisions of "1951 AHSME Problems/Problem 4"

(New page: The answer is (E) 720. 4[50+65]+2[130]=720)
 
 
(4 intermediate revisions by one other user not shown)
Line 1: Line 1:
The answer is (E) 720.
+
==Problem==
 +
A barn with a roof is rectangular in shape, <math>10</math> yd. wide, <math>13</math> yd. long and <math>5</math> yd. high.  It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of sq. yd. to be painted is:
  
4[50+65]+2[130]=720
+
<math> \mathrm{(A) \ } 360 \qquad \mathrm{(B) \ } 460 \qquad \mathrm{(C) \ } 490 \qquad \mathrm{(D) \ } 590 \qquad \mathrm{(E) \ } 720 </math>
 +
 
 +
==Solution==
 +
The walls are <math>13*5=65</math> and <math>10*5=50</math> in area, and the ceiling has an area of <math>10*13=130</math>.
 +
 
 +
<math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}</math>
 +
 
 +
==See Also==
 +
{{AHSME 50p box|year=1951|num-b=3|num-a=5}}
 +
 
 +
[[Category:Introductory Geometry Problems]]
 +
{{MAA Notice}}

Latest revision as of 11:19, 5 July 2013

Problem

A barn with a roof is rectangular in shape, $10$ yd. wide, $13$ yd. long and $5$ yd. high. It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of sq. yd. to be painted is:

$\mathrm{(A) \ } 360 \qquad \mathrm{(B) \ } 460 \qquad \mathrm{(C) \ } 490 \qquad \mathrm{(D) \ } 590 \qquad \mathrm{(E) \ } 720$

Solution

The walls are $13*5=65$ and $10*5=50$ in area, and the ceiling has an area of $10*13=130$.

$((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}$

See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png