Difference between revisions of "2011 AMC 12B Problems/Problem 10"
m |
|||
| Line 9: | Line 9: | ||
== See also == | == See also == | ||
{{AMC12 box|year=2011|ab=B|num-b=9|num-a=11}} | {{AMC12 box|year=2011|ab=B|num-b=9|num-a=11}} | ||
| + | {{MAA Notice}} | ||
Revision as of 10:03, 4 July 2013
Problem
Rectangle 
has 
and 
. Point 
is chosen on side 
so that 
. What is the degree measure of 
?
Solution
Since 
, 
hence 
. Therefore 
. Therefore 
See also
| 2011 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 9 |
Followed by Problem 11 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
