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Difference between revisions of "1992 AJHSME Problems/Problem 16"
Line 61: Line 61:
 
<math>\text{(E)}\ \text{None of the above}</math>
 
<math>\text{(E)}\ \text{None of the above}</math>
  
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==solution==
+
==Solution==
 +
The volume of a cylinder is given by the formula <math>V=\pi r^2 h</math>. The given cylinder therefore has a volume of <math>\pi (10)^2(5)=500\pi</math>. Plugging in the radius and height of the answer choices, we find the cylinder that has a volume of double the volume is <math>\pi (10)^2(10) = 1000\pi \rightarrow \boxed{(B)}</math>.
  
−
 
+
==See Also==
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(B) Cylinder can be obtained b stacking one copy
+
{{AJHSME box|year=1992|num-b=15|num-a=17}}
−
of the given cylinder on top of another. The
 
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formula for the volume of a cylinder with radius
 
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r and the h is V= pi r^2h. Use this to show that
 
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none of the other cylinders has twice the volume
 
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of the given cylinder:
 
−
 
 
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Cylinder- given: pi x 10^2 x 5= 500pi
 
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(A): pi
 

Revision as of 20:45, 22 December 2012

Problem

[asy] draw(ellipse((0,-5),10,3)); fill((-10,-5)--(10,-5)--(10,5)--(-10,5)--cycle,white); draw(ellipse((0,0),10,3)); draw((10,0)--(10,-5)); draw((-10,0)--(-10,-5)); draw((0,0)--(7,-3*sqrt(51)/10)); label("10",(7/2,-3*sqrt(51)/20),NE); label("5",(-10,-3),E); [/asy]

Which cylinder has twice the volume of the cylinder shown above?

[asy] unitsize(4); draw(ellipse((0,-5),20,6)); fill((-20,-5)--(20,-5)--(20,5)--(-20,5)--cycle,white); draw(ellipse((0,0),20,6)); draw((20,0)--(20,-5)); draw((-20,0)--(-20,-5)); draw((0,0)--(14,-3*sqrt(51)/5)); label("20",(7,-3*sqrt(51)/10),NE); label("5",(-20,-4),E); label("(A)",(0,6),N); draw(ellipse((31,-7),10,3)); fill((21,-7)--(41,-7)--(41,7)--(21,7)--cycle,white); draw(ellipse((31,3),10,3)); draw((41,3)--(41,-7)); draw((21,3)--(21,-7)); draw((31,3)--(38,3-3*sqrt(51)/10)); label("10",(34.5,3-3*sqrt(51)/20),NE); label("10",(21,-4),E); label("(B)",(31,6),N); draw(ellipse((47,-15.5),5,3/2)); fill((42,-15.5)--(42,-15.5)--(42,15.5)--(42,15.5)--cycle,white); draw(ellipse((47,4.5),5,3/2)); draw((42,4.5)--(42,-15.5)); draw((52,4.5)--(52,-15.5)); draw((47,4.5)--(50.5,4.5-3*sqrt(51)/20)); label("5",(48.75,4.5-3*sqrt(51)/40),NE); label("10",(42,-6),E); label("(C)",(47,6),N); draw(ellipse((73,-10),20,6)); fill((53,-10)--(93,-10)--(93,5)--(53,5)--cycle,white); draw(ellipse((73,0),20,6)); draw((53,0)--(53,-10)); draw((93,0)--(93,-10)); draw((73,0)--(87,-3*sqrt(51)/5)); label("20",(80,-3*sqrt(51)/10),NE); label("10",(53,-6),E); label("(D)",(73,6),N); [/asy]

$\text{(E)}\ \text{None of the above}$

Solution

The volume of a cylinder is given by the formula $V=\pi r^2 h$. The given cylinder therefore has a volume of $\pi (10)^2(5)=500\pi$. Plugging in the radius and height of the answer choices, we find the cylinder that has a volume of double the volume is $\pi (10)^2(10) = 1000\pi \rightarrow \boxed{(B)}$.

See Also

1992 AJHSME (Problems • Answer Key • Resources)
Preceded by
Problem 15 		Followed by
Problem 17
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions
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