Difference between revisions of "1951 AHSME Problems/Problem 4"

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<math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}</math>
 
<math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}</math>
  
==See also==
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==See Also==
{{AHSME box|year=1951|num-b=3|num-a=5}}  
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{{AHSME 50p box|year=1951|num-b=3|num-a=5}}  
  
 
[[Category:Introductory Geometry Problems]]
 
[[Category:Introductory Geometry Problems]]

Revision as of 07:46, 29 April 2012

Problem

A barn with a roof is rectangular in shape, $10$ yd. wide, $13$ yd. long and $5$ yd. high. It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of sq. yd. to be painted is:

$\mathrm{(A) \ } 360 \qquad \mathrm{(B) \ } 460 \qquad \mathrm{(C) \ } 490 \qquad \mathrm{(D) \ } 590 \qquad \mathrm{(E) \ } 720$

Solution

The walls are $13*5=65$ and $10*5=50$ in area, and the ceiling has an area of $10*13=130$.

$((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}$

See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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All AHSME Problems and Solutions