Difference between revisions of "Mock AIME 1 2006-2007 Problems/Problem 3"
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==Solution== | ==Solution== | ||
| − | {{ | + | By the [[Law of Cosines]], <math>\cos A = \frac{3^2 + 1^2 - \sqrt{7}^2}{2\cdot3\cdot1} = \frac12</math>. Since <math>A</math> is an [[angle]] in a [[triangle]] the only possibility is <math>A = \frac{\pi}{3}</math>. Since <math>\gcd(3, 1000) = 1</math> we may apply [[Euler's totient theorem]]: <math>\phi(1000) = 400</math> so <math>3^{400} \equiv 1 \pmod{1000}</math> and so <math>3^{2000}\equiv 1 \pmod{1000}</math> and so <math>3^{2007} \equiv 3^7 \equiv 2187 \equiv 187 \pmod{1000}</math> |
| + | So the answer is <math>187</math> | ||
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| − | *[[Mock AIME 1 2006-2007/Problem 2 | Previous Problem]] | + | *[[Mock AIME 1 2006-2007 Problems/Problem 2 | Previous Problem]] |
| − | *[[Mock AIME 1 2006-2007/Problem 4 | Next Problem]] | + | *[[Mock AIME 1 2006-2007 Problems/Problem 4 | Next Problem]] |
*[[Mock AIME 1 2006-2007]] | *[[Mock AIME 1 2006-2007]] | ||
Latest revision as of 14:53, 3 April 2012
Let 
have 
, 
, and 
. If 
where 
is an integer, find the remainder when 
is divided by 
.
Solution
By the Law of Cosines, 
. Since 
is an angle in a triangle the only possibility is 
. Since 
we may apply Euler's totient theorem: 
so 
and so 
and so 
So the answer is 
