Difference between revisions of "2012 AIME I Problems/Problem 12"
(Created page with "==Problem 12== == Solution == == See also == {{AIME box|year=2012|n=I|num-b=11|num-a=13}}") |
(→Problem 12) |
||
Line 1: | Line 1: | ||
==Problem 12== | ==Problem 12== | ||
+ | Let <math>\triangle ABC</math> be a right triangle with right angle at <math>C.</math> Let <math>D</math> and <math>E</math> be points on <math>\overline{AB}</math> with <math>D</math> between <math>A</math> and <math>E</math> such that <math>\overline{CD}</math> and <math>\overline{CE}</math> trisect <math>\angle C.</math> If <math>\frac{DE}{BE} = \frac{8}{15},</math> then <math>\tan B</math> can be written as <math>\frac{m \sqrt{p}}{n},</math> where <math>m</math> and <math>n</math> are relatively prime positive integers, and <math>p</math> is a positive integer not divisible by the square of any prime. Find <math>m+n+p.</math> | ||
== Solution == | == Solution == |
Revision as of 00:32, 17 March 2012
Problem 12
Let be a right triangle with right angle at
Let
and
be points on
with
between
and
such that
and
trisect
If
then
can be written as
where
and
are relatively prime positive integers, and
is a positive integer not divisible by the square of any prime. Find
Solution
See also
2012 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |