Difference between revisions of "2010 AMC 8 Problems/Problem 13"
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Revision as of 16:30, 4 March 2012
Contents
Problem
The lengths of the sides of a triangle in inches are three consecutive integers. The length of the shortest side is 
of the perimeter. What is the length of the longest side?
Solution 1
Let 
, 
, and 
be the lengths of the sides of the triangle. Then the perimeter of the triangle is 
. Using the fact that the length of the longest side is of the perimeter, it follows that:
. The longest side is then 
. Thus, answer choice 
is correct.
Solution 2
Since the length of the shortest side is a whole number and is equal to 
of the perimeter, it follows that the perimeter must be a multiple of 
. Adding the two previous integers to each answer choice, we see that 
. Thus, answer choice is correct.
See Also
| 2010 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
