Difference between revisions of "2000 AMC 10 Problems/Problem 9"

(New page: <math>|x-2|=p</math> <math>x<2</math>, so <math>2-x=p</math>. <math>x+p=2</math>. <math>x-p=2-2p</math>.)
 
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<math>|x-2|=p</math>
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#REDIRECT [[2000 AMC 12 Problems/Problem 5]]
<math>x<2</math>, so <math>2-x=p</math>.
 
 
 
<math>x+p=2</math>.
 
<math>x-p=2-2p</math>.
 

Latest revision as of 22:37, 26 November 2011