Difference between revisions of "2000 AMC 10 Problems/Problem 3"

Latest revision as of 22:33, 26 November 2011

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-<math>x \cdot .8 \cdot .8=32</math>
+#REDIRECT [[2000 AMC 12 Problems/Problem 3]]
-<math>x \cdot .64=32</math>
-<math>x \cdot \frac{32}{50}=32</math>
-<math>x=50</math>.
-B.