Difference between revisions of "2000 AMC 10 Problems/Problem 3"

(New page: <math>x \cdot .8 \cdot .8=32</math> <math>x \cdot .64=32</math> <math>x \cdot \frac{32}{50}=32</math> <math>x=50</math>. B.)
 
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<math>x \cdot .8 \cdot .8=32</math>
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#REDIRECT [[2000 AMC 12 Problems/Problem 3]]
<math>x \cdot .64=32</math>
 
<math>x \cdot \frac{32}{50}=32</math>
 
<math>x=50</math>.
 
 
 
B.
 

Latest revision as of 22:33, 26 November 2011