Difference between revisions of "1997 AJHSME Problems/Problem 1"

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Convert each to decimals.
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==Problem==
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<math>\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000} = </math>
  
<cmath>0.1+0.09+0.009+0.0007=0.1997</cmath>
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<math>\text{(A)}\ 0.0026 \qquad \text{(B)}\ 0.0197 \qquad \text{(C)}\ 0.1997 \qquad \text{(D)}\ 0.26 \qquad \text{(E)}\ 1.997</math>
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==Solution==
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Convert each fraction to a decimal.
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<math>\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000}</math>
 +
 
 +
<math>0.1+0.09+0.009+0.0007=0.1997</math>
  
 
<math>\boxed{\textbf{(C)}}</math>
 
<math>\boxed{\textbf{(C)}}</math>
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== See also ==
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{{AJHSME box|year=1998|before=First question|num-a=2}}
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* [[AJHSME]]
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* [[AJHSME Problems and Solutions]]
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* [[Mathematics competition resources]]

Revision as of 12:58, 31 July 2011

Problem

$\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000} =$

$\text{(A)}\ 0.0026 \qquad \text{(B)}\ 0.0197 \qquad \text{(C)}\ 0.1997 \qquad \text{(D)}\ 0.26 \qquad \text{(E)}\ 1.997$

Solution

Convert each fraction to a decimal.

$\dfrac{1}{10} + \dfrac{9}{100} + \dfrac{9}{1000} + \dfrac{7}{10000}$

$0.1+0.09+0.009+0.0007=0.1997$

$\boxed{\textbf{(C)}}$

See also

1998 AJHSME (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions