|
|
| (One intermediate revision by one other user not shown) |
| Line 1: |
Line 1: |
| − | == Problem ==
| + | #REDIRECT[[2003 AMC 12A Problems/Problem 4]] |
| − | It takes Mary <math>30</math> minutes to walk uphill <math>1</math> km from her home to school, but it takes her only <math>10</math> minutes to walk from school to her home along the same route. What is her average speed, in km/hr, for the round trip?
| |
| − | | |
| − | <math> \mathrm{(A) \ } 3\qquad \mathrm{(B) \ } 3.125\qquad \mathrm{(C) \ } 3.5\qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ } 4.5 </math>
| |
| − | | |
| − | == Solution ==
| |
| − | Since she walked <math>1</math> km to school and <math>1</math> km back home, her total distance is <math>1+1=2</math> km.
| |
| − | | |
| − | Since she spent <math>30</math> minutes walking to school and <math>10</math> minutes walking back home, her total time is <math>30+10=40</math> minutes = <math>\frac{40}{60}=\frac{2}{3}</math> hours.
| |
| − | | |
| − | Therefore her average speed in km/hr is <math>\frac{2}{\frac{2}{3}}=3 \Rightarrow A</math>
| |
| − | | |
| − | == See Also ==
| |
| − | *[[2003 AMC 10A Problems]]
| |
| − | *[[2003 AMC 10A Problems/Problem 3|Previous Problem]]
| |
| − | *[[2003 AMC 10A Problems/Problem 5|Next Problem]]
| |
| − | | |
| − | [[Category:Introductory Algebra Problems]]
| |
