Difference between revisions of "1984 AHSME Problems/Problem 6"
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==Problem== | ==Problem== | ||
| − | In a certain school, there are <math> 3 </math> times as many boys as girls and <math> 9 </math> times as many girls as teachers. Using the letters <math> b, g, t </math> to represent the number of boys, girls, and teachers, respectively, then the total number of boys, girls, and teachers can be represented by the expression | + | In a certain school, there are <math> 3 </math> times as many boys as girls and <math> 9 </math> times as many girls as teachers. Using the letters <math> b, g, t </math> to represent the number of boys, girls, and teachers, respectively, then the total number of boys, girls, and teachers can be represented by the [[expression]] |
<math> \mathrm{(A) \ }31b \qquad \mathrm{(B) \ }\frac{37b}{27} \qquad \mathrm{(C) \ } 13g \qquad \mathrm{(D) \ }\frac{37g}{27} \qquad \mathrm{(E) \ } \frac{37t}{27} </math> | <math> \mathrm{(A) \ }31b \qquad \mathrm{(B) \ }\frac{37b}{27} \qquad \mathrm{(C) \ } 13g \qquad \mathrm{(D) \ }\frac{37g}{27} \qquad \mathrm{(E) \ } \frac{37t}{27} </math> | ||
Revision as of 19:59, 16 June 2011
Problem
In a certain school, there are 
times as many boys as girls and 
times as many girls as teachers. Using the letters 
to represent the number of boys, girls, and teachers, respectively, then the total number of boys, girls, and teachers can be represented by the expression
Solution
From the given, we have 
and 
, or 
. The sum of these, in terms of 
, is 
, or, with a common denominator, 
. We can see that this isn't one of the choices. So we write it in terms of 
. We can see from the first equation that 
, so substituting this into the expression yields 
.
See Also
| 1984 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
