Difference between revisions of "2007 AMC 8 Problems/Problem 18"
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− | + | When you multiply <math> 303 </math> by <math> 505 </math>, it's <math> 153015 </math>. The ones digit plus thousands digit is <math> 5 </math> <math> + </math> <math> 3 </math> <math> = </math> <math> 8 </math>. <math> 30303 </math> <math> \times </math> <math> 50505 </math> <math> = </math> <math> 1530453015 </math>. Note that the ones and thousands digits are, added together, <math> 8 </math>. (and so on...) So the answer is <math> \boxed{D} </math> <math> (8) </math>. | |
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Revision as of 01:59, 14 November 2010
When you multiply by , it's . The ones digit plus thousands digit is . . Note that the ones and thousands digits are, added together, . (and so on...) So the answer is .