Difference between revisions of "1998 PMWC Problems/Problem I1"
(Created page with '== Problem I1 == Calculate: <math>\frac{1*2*3+2*4*6+3*6*9+4*8*12+5*10*15}{1*3*5+2*6*10+3*9*15+4*12*20+5*15*25}</math> == Solution == If you factor the top, you get <math>(1*2*3…') |
(→Solution) |
||
| (One intermediate revision by the same user not shown) | |||
| Line 9: | Line 9: | ||
If you factor the bottom, you get <math>(1*3*5)(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})</math> | If you factor the bottom, you get <math>(1*3*5)(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})</math> | ||
| − | Dividing out the common factor, you get < | + | Dividing out the common factor, you get <math>\frac {1*2*3}{1*3*5}=\frac {6}{15}= \frac {2}{5}</math> |
Latest revision as of 15:37, 8 August 2009
Problem I1
Calculate: 
Solution
If you factor the top, you get 
If you factor the bottom, you get 
Dividing out the common factor, you get 
