Difference between revisions of "Talk:1983 AIME Problems/Problem 3"
(New page: I think what the first solution meant to say is that <math>y=-6</math> is an extraneous solution since <math>-6 \neq 2\sqrt{-6+15}</math> (the <math>\sqrt{}</math> symbol is defined as the...) |
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| − | I think what the first solution meant to say is that <math>y=-6</math> is an extraneous solution since <math>-6 \neq 2\sqrt{-6+15}</math> (the <math>\sqrt{}</math> symbol is defined as the positive square root.) Thus, solution one has the correct answer. | + | I think what the first solution meant to say is that <math>y=-6</math> is an extraneous solution since <math>-6 \neq 2\sqrt{-6+15}</math> (the <math>\sqrt{}</math> symbol is defined as the positive square root.) Thus, solution one has the correct answer. |
| + | --[[User:Xantos C. Guin|Xantos C. Guin]] 01:51, 22 May 2009 (UTC) | ||
Latest revision as of 20:51, 21 May 2009
I think what the first solution meant to say is that 
is an extraneous solution since 
(the 
symbol is defined as the positive square root.) Thus, solution one has the correct answer.
--Xantos C. Guin 01:51, 22 May 2009 (UTC)
